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* @license Apache-2.0
*
* Copyright (c) 2026 The Stdlib Authors.
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
'use strict';
// MODULES //
var isnanf = require( '@stdlib/math/base/assert/is-nanf' );
var isInfinitef = require( '@stdlib/math/base/assert/is-infinitef' );
var floorf = require( '@stdlib/math/base/special/floorf' );
var powf = require( '@stdlib/math/base/special/powf' );
var absf = require( '@stdlib/math/base/special/absf' );
var log10 = require( '@stdlib/math/base/special/log10' );
var f32 = require( '@stdlib/number/float64/base/to-float32' );
// MAIN //
/**
* Rounds a single-precision floating-point number to the nearest power of `10` on a linear scale.
*
* @param {number} x - input value
* @returns {number} rounded value
*
* @example
* var v = round10f( 3.1415926 );
* // returns 1.0
*
* @example
* var v = round10f( 123.45 );
* // returns 100.0
*
* @example
* var v = round10f( -2.5 );
* // returns -1.0
*
* @example
* var v = round10f( -0.0 );
* // returns -0.0
*/
function round10f( x ) {
var ax;
var e0;
var e1;
var y0;
var y1;
x = f32( x );
if ( isnanf( x ) || isInfinitef( x ) || x === 0.0 ) {
return x;
}
ax = absf( x );
// Solve the equation `10^e = ax` for `e` and find the exponent of the previous integer power of ten:
e0 = floorf( f32( log10( ax ) ) );
// Find the exponent of the next integer power of ten:
e1 = f32( e0 + 1 );
// Compute the previous and next integer powers of ten:
y0 = powf( 10.0, e0 );
y1 = powf( 10.0, e1 );
// Find the closest power of ten, rounding ties to the next integer power of ten (note: as single-precision values are exactly representable in double-precision and the operands are of similar magnitude, both differences are computed exactly in double-precision arithmetic):
if ( ax - y0 < y1 - ax ) {
return ( x < 0.0 ) ? f32( -y0 ) : y0;
}
return ( x < 0.0 ) ? f32( -y1 ) : y1;
}
// EXPORTS //
module.exports = round10f;
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